Analytical Reasoning Question No. 32
A chemist has exactly four unlabeled glasses containing colorless liquids standing on a laboratory shelf. The chemist knows that the only six liquids that the glasses could possibly contain are pure M, pure N, pure O, or any combination of two of these, and that no two glasses are filled with the same liquid. The only feasible way of testing for the identity of the liquids is to use strips of a special white reactive paper that turns Green, Brown, or Purple, depending on which of certain liquids it is dipped in. The full table of color changes and of the triggers for those changes is given below:
| Green | Brown | Purple |
|---|---|---|
| Pure N | Pure M | M combine with N |
| N combine with O | Pure O | M combine with O |
| M, N, and O combine together |
1. If none of the four liquids turns the reactive paper Purple, each of the following must be the contents of one of the glasses EXCEPT
(A) pure M
(B) pure N
(C) pure O
(D) N combined with O
(E) M, N, and O combined together
2. If the liquid in the first glass tested turns the reactive paper Green, and if the liquid in the second glass tested turns the paper Purple, then a combination of some of the liquid from each of the first two glasses tested will turn the reactive paper
(A) Green
(B) Purple
(C) either Green or Brown
(D) either Green or Purple
(E) either Brown or Purple
3. If the liquid in the first glass tested turns the reactive paper Green and the liquid in the second glass tested turns it Brown, and if a combination of some of the liquid from each of the first two glasses tested turns it Green, then which of the following must be true?
(A) The first glass tested contains pure N.
(B) The first glass tested contains N combined with O.
(C) The second glass tested contains pure M.
(D) The second glass tested contains pure O.
(E) The second glass tested contains N combined with O.
For correct option please click here
▶ Watch Video Solution
